Ontologia

Ruisseau· 5 segments

Tensfelder Au

Crosses 3 administrative regions : Ostholstein, Plön, Segeberg

ruisseau

Total length

11km

Max discharge

1,1m³/s

Max Strahler

2

Segments matched

5

River geography3 admin regions · 0 communes

Parent watershed

hybas-2080025550682 km²

3 administrative regions crossed (GADM L2)

  • Segeberg
    Schleswig-Holstein · Germany
    8.6 km
    in this dpt
  • Plön
    Schleswig-Holstein · Germany
    4.4 km
    in this dpt
  • Ostholstein
    Schleswig-Holstein · Germany
    0.0 km
    in this dpt

8 intersecting protected areas

1 page = 1 named river (aggregation of 5 HydroRIVERS v10 segments). Spatial join cached after first hit.

Species present

996 distinct species · 2 589 observations

Source: GBIF Occurrence snapshot 2026-05-01.

Ecological tissue

Sample of 38 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.

ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).

RègnesAnimalPlanteChampignonBacterie
RelationsPredationParasitismeSymbiosePollinisation
StatutEn dangerVulnérableProtégéeEndémique

Indicateurs du tissu écologique

Tissu écologique de Tensfelder Au : 26 espèces reliées par 112 interactions GloBI sur 6 types (connectance 15.9%, filtre Serrano α=0.2). 12 bulles taxonomiques (cascade genre/famille GloBI, ≥3 espèces).

Espèces affichées
38
Interactions affichées
112
Connectance
0.159
Patrimoniales
0
Plus dense que (national)0 %(top 100%)

Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).

Hydrology (HydroRIVERS v10)

Total length

11km

Max discharge

1,1m³/s

Max Strahler

2

Segments matched

5

HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.