Rivière· 4 segments
Sennan
Crosses 1 administrative regions : Halmstad
Total length
10km
Max discharge
43,8m³/s
Max Strahler
4
Segments matched
4
River geography1 admin regions · 0 communes
1 administrative regions crossed (GADM L2)
- HalmstadHalland · Sweden12.1 kmin this dpt
10 intersecting protected areas
2051221 Keddaböke
IUCN IVNature Reserve
2050159 Finnsboskogen
IUCN IaNature Reserve
Virsehatt
IUCN Not ReportedSpecial Areas of Conservation (Habitats Directive)
Virsehatt
IUCN IVNatura 2000 SCI
2001399 Virsehatt
IUCN IVNature Reserve
Nature Reserve
SK 230-2010
IUCN IaHabitat Protection Area
SK 196-2015
IUCN IVNature conservation agreement, Swedish Forest Agency
SK 294-2013
IUCN IVNature conservation agreement, Swedish Forest Agency
1 more protected areassorted by area
SK 1004-2004
IUCN IaHabitat Protection Area
1 page = 1 named river (aggregation of 4 HydroRIVERS v10 segments). Spatial join cached after first hit.
Species present
2 330 distinct species · 18 241 observations
Source: GBIF Occurrence snapshot 2026-05-01.
Ecological tissue
Sample of 40 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.
ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).
Indicateurs du tissu écologique
Tissu écologique de Sennan : 33 espèces dont 1 patrimoniale (LR IUCN CR/EN/VU) reliées par 86 interactions GloBI sur 4 types (connectance 9.5%, filtre Serrano α=0.2). 10 bulles taxonomiques (cascade genre/famille GloBI, ≥3 espèces).
Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).
Hydrology (HydroRIVERS v10)
Total length
10km
Max discharge
43,8m³/s
Max Strahler
4
Segments matched
4
HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.