Ontologia

Rivière· 12 segments

Свіслач

Crosses 4 administrative regions : Byerastavitsa, Hrodna, Sokółka, Svislach

rivière

Total length

335km

Max discharge

9,9m³/s

Max Strahler

4

Segments matched

12

River geography4 admin regions · 0 communes

Parent watershed

hybas-20803396901740 km²

4 administrative regions crossed (GADM L2)

  • Byerastavitsa
    Grodno · Belarus
    25.6 km
    in this dpt
  • Hrodna
    Grodno · Belarus
    14.7 km
    in this dpt
  • Svislach
    Grodno · Belarus
    10.6 km
    in this dpt
  • Sokółka
    Podlaskie · Poland
    2.8 km
    in this dpt

2 intersecting protected areas

1 page = 1 named river (aggregation of 12 HydroRIVERS v10 segments). Spatial join cached after first hit.

Species present

7 distinct species · 16 observations

Source: GBIF Occurrence snapshot 2026-05-01.

Ecological tissue

Sample of 7 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.

ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).

RègnesAnimalPlanteChampignonBacterie
RelationsPredationParasitismeSymbiosePollinisation
StatutEn dangerVulnérableProtégéeEndémique

Indicateurs du tissu écologique

Tissu écologique de Свіслач : 7 espèces dont 1 patrimoniale (LR IUCN CR/EN/VU) reliées par 4 interactions GloBI sur 2 types (connectance 19.0%, filtre Serrano α=0.2).

Espèces affichées
7
Interactions affichées
4
Connectance
0.191
Patrimoniales
1
Plus dense que (national)0 %(top 100%)

Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).

Hydrology (HydroRIVERS v10)

Total length

335km

Max discharge

9,9m³/s

Max Strahler

4

Segments matched

12

HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.