Rivière· 74 segments
Rio Pardo
Crosses 11 administrative regions : Barros Cassal, Candelária, Gramado Xavier, Herveiras, Lagoão +6
Total length
3 331km
Max discharge
1 123,9m³/s
Max Strahler
6
Segments matched
74
River geography11 admin regions · 0 communes
11 administrative regions crossed (GADM L2)
- Barros CassalRio Grande do Sul · Brazil49.3 kmin this dpt
- CandeláriaRio Grande do Sul · Brazil46.0 kmin this dpt
- Rio PardoRio Grande do Sul · Brazil33.9 kmin this dpt
- LagoãoRio Grande do Sul · Brazil26.6 kmin this dpt
- Gramado XavierRio Grande do Sul · Brazil14.7 kmin this dpt
- Vale do SolRio Grande do Sul · Brazil12.3 kmin this dpt
- SinimbuRio Grande do Sul · Brazil11.2 kmin this dpt
- Passa SeteRio Grande do Sul · Brazil11.0 kmin this dpt
- Vera CruzRio Grande do Sul · Brazil10.3 kmin this dpt
- HerveirasRio Grande do Sul · Brazil3.4 kmin this dpt
- Santa Cruz do SulRio Grande do Sul · Brazil3.3 kmin this dpt
1 page = 1 named river (aggregation of 74 HydroRIVERS v10 segments). Spatial join cached after first hit.
Species present
8 distinct species · 8 observations
Source: GBIF Occurrence snapshot 2026-05-01.
Ecological tissue
Sample of 2 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.
ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).
Indicateurs du tissu écologique
Tissu écologique de Rio Pardo : 2 espèces reliées par 1 interaction GloBI sur 1 type (connectance 100.0%, filtre Serrano α=0.2).
Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).
Hydrology (HydroRIVERS v10)
Total length
3 331km
Max discharge
1 123,9m³/s
Max Strahler
6
Segments matched
74
HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.