Ontologia

Rivière· 19 segments

Pawcatuck River

Crosses 2 administrative regions : New London, Washington

rivière

Total length

55km

Max discharge

16,2m³/s

Max Strahler

4

Segments matched

19

River geography2 admin regions · 0 communes

Parent watershed

hybas-7080039570802 km²

2 administrative regions crossed (GADM L2)

  • Washington
    Rhode Island · United States
    53.3 km
    in this dpt
  • New London
    Connecticut · United States
    7.8 km
    in this dpt

30 intersecting protected areas

21 more protected areas

1 page = 1 named river (aggregation of 19 HydroRIVERS v10 segments). Spatial join cached after first hit.

Species present

779 distinct species · 8 974 observations

Source: GBIF Occurrence snapshot 2026-05-01.

Ecological tissue

Sample of 45 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.

ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).

RègnesAnimalPlanteChampignonBacterie
RelationsPredationParasitismeSymbiosePollinisation
StatutEn dangerVulnérableProtégéeEndémique

Indicateurs du tissu écologique

Tissu écologique de Pawcatuck River : 30 espèces dont 1 patrimoniale (LR IUCN CR/EN/VU) reliées par 104 interactions GloBI sur 4 types (connectance 10.5%, filtre Serrano α=0.2). 15 bulles taxonomiques (cascade genre/famille GloBI, ≥3 espèces).

Espèces affichées
45
Interactions affichées
104
Connectance
0.105
Patrimoniales
1
Plus dense que (national)0 %(top 100%)

Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).

Hydrology (HydroRIVERS v10)

Total length

55km

Max discharge

16,2m³/s

Max Strahler

4

Segments matched

19

HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.