Ontologia

Ruisseau· 8 segments

Lawrence Brook

Crosses 3 administrative regions : Franklin, Lamoille, Saint Lawrence

ruisseau

Total length

80km

Max discharge

1,8m³/s

Max Strahler

2

Segments matched

8

River geography3 admin regions · 0 communes

Parent watershed

hybas-70804121802220 km²

3 administrative regions crossed (GADM L2)

  • Franklin
    New York · United States
    26.1 km
    in this dpt
  • Saint Lawrence
    New York · United States
    4.5 km
    in this dpt
  • Lamoille
    Vermont · United States
    1.6 km
    in this dpt

5 intersecting protected areas

1 page = 1 named river (aggregation of 8 HydroRIVERS v10 segments). Spatial join cached after first hit.

Species present

143 distinct species · 1 796 observations

Source: GBIF Occurrence snapshot 2026-05-01.

Ecological tissue

Sample of 35 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.

ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).

RègnesAnimalPlanteChampignonBacterie
RelationsPredationParasitismeSymbiosePollinisation
StatutEn dangerVulnérableProtégéeEndémique

Indicateurs du tissu écologique

Tissu écologique de Lawrence Brook : 25 espèces reliées par 75 interactions GloBI sur 4 types (connectance 11.9%, filtre Serrano α=0.2). 11 bulles taxonomiques (cascade genre/famille GloBI, ≥3 espèces).

Espèces affichées
36
Interactions affichées
75
Connectance
0.119
Patrimoniales
0
Plus dense que (national)0 %(top 100%)

Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).

Hydrology (HydroRIVERS v10)

Total length

80km

Max discharge

1,8m³/s

Max Strahler

2

Segments matched

8

HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.