Ontologia

Ruisseau· 11 segments

Hemphill Creek

Crosses 3 administrative regions : Haywood, La Salle, Rapides

ruisseau

Total length

68km

Max discharge

2,3m³/s

Max Strahler

2

Segments matched

11

River geography3 admin regions · 0 communes

Parent watershed

hybas-7080732230828 km²

3 administrative regions crossed (GADM L2)

  • La Salle
    Louisiana · United States
    22.0 km
    in this dpt
  • Rapides
    Louisiana · United States
    9.8 km
    in this dpt
  • Haywood
    North Carolina · United States
    4.4 km
    in this dpt

2 intersecting protected areas

1 page = 1 named river (aggregation of 11 HydroRIVERS v10 segments). Spatial join cached after first hit.

Species present

581 distinct species · 1 260 observations

Source: GBIF Occurrence snapshot 2026-05-01.

Ecological tissue

Sample of 47 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.

ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).

RègnesAnimalPlanteChampignonBacterie
RelationsPredationParasitismeSymbiosePollinisation
StatutEn dangerVulnérableProtégéeEndémique

Indicateurs du tissu écologique

Tissu écologique de Hemphill Creek : 26 espèces reliées par 142 interactions GloBI sur 4 types (connectance 12.1%, filtre Serrano α=0.2). 23 bulles taxonomiques (cascade genre/famille GloBI, ≥3 espèces).

Espèces affichées
49
Interactions affichées
142
Connectance
0.121
Patrimoniales
0
Plus dense que (national)0 %(top 100%)

Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).

Hydrology (HydroRIVERS v10)

Total length

68km

Max discharge

2,3m³/s

Max Strahler

2

Segments matched

11

HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.