Ontologia

Ruisseau· 20 segments

Foglia

Crosses 3 administrative regions : Arezzo, Pesaro E Urbino, Rimini

ruisseau

Total length

89km

Max discharge

9,5m³/s

Max Strahler

3

Segments matched

20

River geography3 admin regions · 0 communes

Parent watershed

hybas-2080013300700 km²

3 administrative regions crossed (GADM L2)

  • Pesaro E Urbino
    Marche · Italy
    77.0 km
    in this dpt
  • Rimini
    Emilia-Romagna · Italy
    0.0 km
    in this dpt
  • Arezzo
    Toscana · Italy
    0.0 km
    in this dpt

6 intersecting protected areas

1 page = 1 named river (aggregation of 20 HydroRIVERS v10 segments). Spatial join cached after first hit.

Species present

196 distinct species · 493 observations

Source: GBIF Occurrence snapshot 2026-05-01.

Ecological tissue

Sample of 32 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.

ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).

RègnesAnimalPlanteChampignonBacterie
RelationsPredationParasitismeSymbiosePollinisation
StatutEn dangerVulnérableProtégéeEndémique

Indicateurs du tissu écologique

Tissu écologique de Foglia : 21 espèces dont 1 patrimoniale (LR IUCN CR/EN/VU) reliées par 91 interactions GloBI sur 3 types (connectance 17.2%, filtre Serrano α=0.2). 12 bulles taxonomiques (cascade genre/famille GloBI, ≥3 espèces).

Espèces affichées
33
Interactions affichées
91
Connectance
0.172
Patrimoniales
1
Plus dense que (national)0 %(top 100%)

Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).

Hydrology (HydroRIVERS v10)

Total length

89km

Max discharge

9,5m³/s

Max Strahler

3

Segments matched

20

HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.