Ontologia

Ruisseau· 17 segments

East Fork Duck Creek

Crosses 3 administrative regions : Noble, Sweet Grass, Washington

ruisseau

Total length

78km

Max discharge

3,4m³/s

Max Strahler

3

Segments matched

17

River geography3 admin regions · 0 communes

Parent watershed

hybas-7080555650763 km²

3 administrative regions crossed (GADM L2)

  • Noble
    Ohio · United States
    43.5 km
    in this dpt
  • Sweet Grass
    Montana · United States
    16.8 km
    in this dpt
  • Washington
    Ohio · United States
    5.2 km
    in this dpt

1 intersecting protected areas

1 page = 1 named river (aggregation of 17 HydroRIVERS v10 segments). Spatial join cached after first hit.

Species present

763 distinct species · 6 001 observations

Source: GBIF Occurrence snapshot 2026-05-01.

Ecological tissue

Sample of 44 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.

ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).

RègnesAnimalPlanteChampignonBacterie
RelationsPredationParasitismeSymbiosePollinisation
StatutEn dangerVulnérableProtégéeEndémique

Indicateurs du tissu écologique

Tissu écologique de East Fork Duck Creek : 35 espèces reliées par 82 interactions GloBI sur 4 types (connectance 8.3%, filtre Serrano α=0.2). 10 bulles taxonomiques (cascade genre/famille GloBI, ≥3 espèces).

Espèces affichées
45
Interactions affichées
82
Connectance
0.083
Patrimoniales
0
Plus dense que (national)0 %(top 100%)

Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).

Hydrology (HydroRIVERS v10)

Total length

78km

Max discharge

3,4m³/s

Max Strahler

3

Segments matched

17

HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.