Ontologia

Ruisseau· 18 segments

Brokenstraw Creek

Crosses 3 administrative regions : Chautauqua, Erie, Warren

ruisseau

Total length

94km

Max discharge

14,1m³/s

Max Strahler

3

Segments matched

18

River geography3 admin regions · 0 communes

Parent watershed

hybas-7080494930864 km²

3 administrative regions crossed (GADM L2)

  • Warren
    Pennsylvania · United States
    57.1 km
    in this dpt
  • Chautauqua
    New York · United States
    16.1 km
    in this dpt
  • Erie
    Pennsylvania · United States
    2.1 km
    in this dpt

7 intersecting protected areas

1 page = 1 named river (aggregation of 18 HydroRIVERS v10 segments). Spatial join cached after first hit.

Species present

230 distinct species · 502 observations

Source: GBIF Occurrence snapshot 2026-05-01.

Ecological tissue

Sample of 54 species (selected proportionally per kingdom among those with at least one documented interaction here) to keep the graph readable. Hover for details, click to explore the full ecosystem of a species.

ℹ️ The territory contains many more species than displayed and all their documented interactions: the graph is intentionally the structural skeleton (top-N species by composite local score, edges filtered by Serrano 2009 disparity filter α=0.2).

RègnesAnimalPlanteChampignonBacterie
RelationsPredationParasitismeSymbiosePollinisation
StatutEn dangerVulnérableProtégéeEndémique

Indicateurs du tissu écologique

Tissu écologique de Brokenstraw Creek : 42 espèces reliées par 118 interactions GloBI sur 5 types (connectance 8.2%, filtre Serrano α=0.2). 12 bulles taxonomiques (cascade genre/famille GloBI, ≥3 espèces).

Espèces affichées
54
Interactions affichées
118
Connectance
0.083
Patrimoniales
0
Plus dense que (national)0 %(top 100%)

Comparaison sur la connectance du réseau local complet vs distribution nationale (toutes les communes françaises).

Hydrology (HydroRIVERS v10)

Total length

94km

Max discharge

14,1m³/s

Max Strahler

3

Segments matched

18

HydroRIVERS v1.0 (Lehner et al. 2019) aggregated by name + main_riv → 1 entity = 1 named river.